From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 3250/CH4/EX4.4/Ex4_4.sce | 25 +++++++++++++++++++++++++
 1 file changed, 25 insertions(+)
 create mode 100755 3250/CH4/EX4.4/Ex4_4.sce

(limited to '3250/CH4/EX4.4/Ex4_4.sce')

diff --git a/3250/CH4/EX4.4/Ex4_4.sce b/3250/CH4/EX4.4/Ex4_4.sce
new file mode 100755
index 000000000..319c7254a
--- /dev/null
+++ b/3250/CH4/EX4.4/Ex4_4.sce
@@ -0,0 +1,25 @@
+clc 
+// Given that
+alpha = 10 // Rake angle of tool in Degree
+v = 200 // Cutting speed in m/min
+t1 = 0.2 // Uncut thickness in mm
+w = 2 // Width of cut in mm
+mu = 0.5 // Avg value of the cofficient of tbe friction
+T_S = 400 // Shear stress of the work material in N/mm^2
+Cm = 70 // Machining constant in Degree
+// Sample Problem 4 on page no. 194
+printf("\n # PROBLEM 4.4 # \n")
+lambda = atand(mu)
+phi = (Cm + alpha - lambda)/2
+Fs = (w*t1*T_S)/(sind(phi))
+R = Fs/(cosd(phi+lambda-alpha))
+Fc = R*(cosd(lambda-alpha))
+Ft = R*(sind(lambda-alpha))
+// Using Lee and Shaffer relation 
+phi_ = 45-lambda+alpha
+Fs_ = (w*t1*T_S)/(sind(phi_))
+R_ = Fs_/(cosd(phi_+lambda-alpha))
+Fc_ = R_*(cosd(lambda-alpha))
+Ft_ = R_*(sind(lambda-alpha))
+printf("\n Shear angle = %f°, \n Cutting force = %f N, \n Thrust force = %f N \n Using Lee and Shaffer relation- \n Shear angle = %f°, \n Cutting force = %f N, \n Thrust force = %f N,",phi,Fc,Ft,phi_,Fc_,Ft_)
+// Answer in the book for cutting force is given as 486.9 N and for thrust force is given as 144.9 N , When using Lee and Shaffer relation answer in the book for cutting force is given as 481.9 N and for trust force is given as 160.6 N
-- 
cgit