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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /317/CH7/EX7.8/example8.sce | |
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-rwxr-xr-x | 317/CH7/EX7.8/example8.sce | 25 |
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diff --git a/317/CH7/EX7.8/example8.sce b/317/CH7/EX7.8/example8.sce new file mode 100755 index 000000000..bff4181d8 --- /dev/null +++ b/317/CH7/EX7.8/example8.sce @@ -0,0 +1,25 @@ +// find the 2 values of output voltage +// Electronic Principles +// By Albert Malvino , David Bates +// Seventh Edition +// The McGraw-Hill Companies +// Example 7-8, page 236 + +clear;clc; close; + +// Given data +Vcc=5;// collector supply voltage in volts +Vbb=10;// base voltage in volts +Rc=1*10^3;// collector resistance in ohms +Rb=10*10^3;// base resistance in ohms +Bdc=50;// current gain +Vcesat=0.15;// saturation voltage in volts +Iceo=50*10^-9;// collector leakage current in amperes + +// Calculations +Vce=Vcc-(Iceo*Rc);// collector-emitter voltage in volts +disp("Volts",Vcesat,"Output voltage") +disp("Volts",Vce,"Output voltage") + +// Result +// the 2 output voltages are 5 volts and 0.15 volts |