initial commit / add all books

10 files changed, 80 insertions, 0 deletions

diff --git a/3159/CH5/EX5.1/Ex5_1.sce b/3159/CH5/EX5.1/Ex5_1.sce
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+// Calculate packing efficiency and density of diamond

+clc

+n_c = 1/8 // sharing of corner atom in a unit cell

+N_c = 8 // Number of corner atoms in unit cell

+n_b = 1 // sharing of body centered atom in a unit cell

+N_b = 4 // Number of body centered atoms in unit cell

+n_f = 0.5// sharing of face centered atom in a unit cell

+N_f = 6// Number of face centered atoms in unit cell

+a = 1 // let lattice parameter

+m = 12 // mass of carbon

+printf("\n Example 5.1")

+printf("\n Part A:")

+N = n_c*N_c+n_b*N_b+n_f*N_f // effective number of atoms

+r = a*sqrt(3)/8

+p_e = N*4/3*%pi*r^3/a^3 // packing efficiency

+

+printf("\n Packing efficiency of diamond is %.2f",p_e)

+printf("\n\n Part B:")

+a = 3.57 // lattice parameter in angstrom

+d = m*1.66e-27*N/(a*1e-10)^3

+printf("\n Density of diamond is %d Kg/m^3",d)// numerical answer in book is 3500

+printf("\n Density of diamond is %.1f g/cm^3",d/1000)

diff --git a/3159/CH5/EX5.1/Ex5_1.txt b/3159/CH5/EX5.1/Ex5_1.txt
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+ 

+ Example 5.1

+ Part A:

+ Packing efficiency of diamond is 0.34

+

+ Part B:

+ Density of diamond is 3502 Kg/m^3

+ Density of diamond is 3.5 g/cm^3 
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diff --git a/3159/CH5/EX5.3/Ex5_3.sce b/3159/CH5/EX5.3/Ex5_3.sce
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index 000000000..2942a912e
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+// calculate the c/a ratio for an ideally close packed HCP crystal

+clc

+a = 1 // let

+PR = a

+printf("\ Example 5.3")

+RT = a/sqrt(3)

+PT = sqrt(PR^2-RT^2)

+c_a = 2*PT/PR

+// Calculations are made on the crystal structure drawn in book

+printf("\n c/a ratio for an ideally close packed HCP crystal is %0.3f ",c_a)

+

diff --git a/3159/CH5/EX5.3/Ex5_3.txt b/3159/CH5/EX5.3/Ex5_3.txt
new file mode 100755
index 000000000..f6e5db4c2
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+++ b/3159/CH5/EX5.3/Ex5_3.txt
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+  Example 5.3

+ c/a ratio for an ideally close packed HCP crystal is 1.633  
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diff --git a/3159/CH5/EX5.4/Ex5_4.sce b/3159/CH5/EX5.4/Ex5_4.sce
new file mode 100755
index 000000000..e06aaf6bd
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+++ b/3159/CH5/EX5.4/Ex5_4.sce
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+// find the size of largest sphere that can fit into a tetrahedral void

+clc

+r = 1 // let

+a = 3/4 

+printf("\n Example 5.4")

+pt = 2*sqrt(2/3)*r

+s = a*pt-r // size of sphere

+printf("\n Size of largest sphere that can fit into a tetrahedral void is %.3fr",s)

+

diff --git a/3159/CH5/EX5.4/Ex5_4.txt b/3159/CH5/EX5.4/Ex5_4.txt
new file mode 100755
index 000000000..3ed50986c
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+

+ Example 5.4

+ Size of largest sphere that can fit into a tetrahedral void is 0.225r 
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diff --git a/3159/CH5/EX5.5/Ex5_5.sce b/3159/CH5/EX5.5/Ex5_5.sce
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index 000000000..fffe2b017
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+// find critical radius ratio for triangular coordination

+clc

+theta = 60 // angle in degree

+printf("\n Example 5.5")

+r_c_a = (2/3*2*sin(theta*%pi/180))-1 // ratio calculation

+printf("\n Critical radius ratio for triangular coordination is %0.3f ",r_c_a)

diff --git a/3159/CH5/EX5.5/Ex5_5.txt b/3159/CH5/EX5.5/Ex5_5.txt
new file mode 100755
index 000000000..5c520a503
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+++ b/3159/CH5/EX5.5/Ex5_5.txt
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+ 

+ Example 5.5

+ Critical radius ratio for triangular coordination is 0.155  
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diff --git a/3159/CH5/EX5.6/Ex5_6.sce b/3159/CH5/EX5.6/Ex5_6.sce
new file mode 100755
index 000000000..37cb2f6cb
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+// Calculate density of MgO

+clc

+r_mg = 0.78 // radius of magnesium cation in angstrom

+r_o = 1.32 // radius of oxygen anion in angstrom

+n = 4 // effective number of unit cell

+m_o = 16 // mass of oxygen

+m_mg = 24.3 // mass of magnesium

+printf("\n Example 5.6")

+a = 2*(r_mg+r_o)// lattice parameter

+d = (m_o+m_mg)*1.66e-27*n/(a*1e-10)^3// density 

+printf("\n Density of MgO is %d Kg/m^3",d) // answer is 3610 kg/m^3

+printf("\n Density of MgO is %0.2f g/cm^3",d/1000)

diff --git a/3159/CH5/EX5.6/Ex5_6.txt b/3159/CH5/EX5.6/Ex5_6.txt
new file mode 100755
index 000000000..2b2fb66c2
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+

+ Example 5.6

+ Density of MgO is 3611 Kg/m^3

+ Density of MgO is 3.61 g/cm^3 
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