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authorpriyanka2015-06-24 15:03:17 +0530
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+clc;
+clear;
+mprintf('MACHINE DESIGN \n Timothy H. Wentzell, P.E. \n EXAMPLE-5.1 Page No.93\n');
+
+SF=2; //[] Safety factor
+F=500; //[lb] Load
+L=40; //[in] Length of shaft
+Su=95000; //[lb/in^2] Ultimate strength (Appendix 4)
+Sy=60000; //[lb/in^2] Yield strength (Appendix 4)
+
+Mmax=F*L/4; //[lb*in] Maximum bending moment
+Mmin=-F*L/4; //[lb/in^2] Minimum bending moment
+
+Csurface=1; //[] As surface is polished
+Csize=0.85; //[] Assuming 0.5<D<2
+Ctype=1; //[] Bending stress
+
+Sn=Csize*Csurface*Ctype*(0.5*Su); //[lb/in^2] Endurance limit
+
+if Mmax==abs(Mmin) then
+ Sm=0; //[lb/in^2] Mean stress
+end
+
+Sa=Sn/SF; //[lb/in^2] As (1/SF)=(Sm/Sy)+(Sa/Sn) from soderberg equation
+
+Sa_Z=(Mmax-Mmin)/2; //[lb*in^2] Product of altenating stress and section modulus
+
+Z=Sa_Z/Sa; //[in^4] Section modulus
+
+D=(32*Z/%pi)^(1/3); //[in] Diameter of shaft
+
+D1=1.375; //[in] Next higher available is 1.375 in. so use D1
+
+mprintf('\n The required diameter of rotating shaft is %f in.', D1);