initial commit / add all books

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+

+//Find percentage variation in load current and load voltage

+clear;

+clc;

+//soltion

+//given

+Vs=10;//volt//Supply voltage

+Rs=100;//ohm//internal resistance

+

+// In accordance to figure 1.24a

+//For 1Ω - 10 Ω

+Rl11=1;//ohm//min extreme value of Rl

+Rl12=10;//ohm//max extreme value of Rl

+Il11=Vs/(Rs+Rl11);

+Il12=Vs/(Rs+Rl12);

+Pi1=(Il11-Il12)*100/Il11;//Percentage variation in current

+Vl11=Il11*Rl11;

+Vl12=Il12*Rl12;

+Pv1=(Vl12-Vl11)*100/Vl12;//Percentage variation in voltage

+printf("\nIn accordance to figure 1.24a \n");

+printf("Percentage variation in Current(1-10 Ω) %.2f percent\n",Pi1);

+printf("Percentage variation in Voltage(1-10 Ω) %.1f percent\n\n",Pv1);

+

+// In accordance to figure 1.24b

+//For 1kΩ - 10kΩ

+Rl21=1000;//ohm//min extreme value of Rl

+Rl22=10000;//ohm//max extreme value of Rl

+Il21=Vs/(Rs+Rl21);

+Il22=Vs/(Rs+Rl22);

+Pi2=(Il21-Il22)*100/Il21;//Percentage variation in current

+Vl21=Il21*Rl21;

+Vl22=Il22*Rl22;

+Pv2=(Vl22-Vl21)*100/Vl22;//Percentage variation in voltage

+printf("\nIn accordance to figure 1.24b \n");

+printf("Percentage variation in Current(1-10 Ω) %d percent \n",Pi2);

+printf("Percentage variation in Voltage(1-10 Ω) %.1f percent \n\n",Pv2);

+// In book the percentage variation in voltage(1kΩ-10kΩ) is 9 percent due to 

+// the incorrect value of Il22 i.e. 0.000999 Amp correct value is 0.0009901 Amp