initial commit / add all books

4 files changed, 107 insertions, 0 deletions

diff --git a/2885/CH1/EX1.1/ex1_1.sce b/2885/CH1/EX1.1/ex1_1.sce
new file mode 100755
index 000000000..d2cc84a71
--- /dev/null
+++ b/2885/CH1/EX1.1/ex1_1.sce
@@ -0,0 +1,22 @@
+//Find the range of tolerance

+clear;

+clc;

+//soltion

+//given

+

+//color coding

+orange=3;

+gold=5;

+yellow=4;

+violet=7;

+//band pattern

+band1=yellow;

+band2=violet;

+band3=orange;

+band4=gold;

+//resistor color coding

+r=(band1*10+band2)*10^(band3);

+tol=r*(band4/100)//tolerance

+ulr=r+tol;//upper limit of resistance

+llr=r-tol;//lower limit of resistance

+printf('The Range of resistance is %.2f kΩ to %.2f kΩ',llr/1000,ulr/1000);

diff --git a/2885/CH1/EX1.2/ex1_2.sce b/2885/CH1/EX1.2/ex1_2.sce
new file mode 100755
index 000000000..5262e2892
--- /dev/null
+++ b/2885/CH1/EX1.2/ex1_2.sce
@@ -0,0 +1,22 @@
+//Find the range of tolerance

+clear;

+clc;

+//soltion

+//given

+

+//color coding

+blue=6;

+gold=-1;

+gray=8;

+silver=10;

+//band pattern

+band1=gray;

+band2=blue;

+band3=gold;

+band4=silver;

+//resistor color coding

+r=(band1*10+band2)*10^(band3);

+tol=r*(band4/100)//tolerance

+ulr=r+tol;//upper limit of resistance

+llr=r-tol;//lower limit of resistance

+printf('The Range of resistance is %.2f Ω to %.2f Ω',llr,ulr);

diff --git a/2885/CH1/EX1.3/ex1_3.sce b/2885/CH1/EX1.3/ex1_3.sce
new file mode 100755
index 000000000..87d8749d2
--- /dev/null
+++ b/2885/CH1/EX1.3/ex1_3.sce
@@ -0,0 +1,25 @@
+

+//Find the equivalent current source

+clear;

+clc;

+//soltion

+//given

+Vs=2;//Volts             //dc voltage source

+Rs=1;//ohm               //internal resistance

+Rl=1;//ohm              //load resistance

+Ise=Vs/Rs;//ampere      //equivalent current source

+

+// In accordance to figure 1.23a

+Il1=Ise*(Rs/(Rs+Rl));//using current divider concept

+Vl1=Il1*Rl;

+printf("\nIn accordance to figure 1.23a \n");

+printf("The Load current (current source) Il= %dA\n",Il1);

+printf("The Load voltage (current source) Vl= %dV\n\n",Vl1);

+

+// In accordance to figure 1.23b

+Vl2=Vs*(Rs/(Rs+Rl));//using voltage divider concept

+Il2=Vl2/Rl;

+printf("\nIn accordance to figure 1.23b \n");

+printf("The Load voltage (voltage source) Vl= %dV\n",Vl2);

+printf("The Load current (voltage source) Il= %dA\n\n",Il2);

+printf("Therefore they both provide same voltage and current to load");

diff --git a/2885/CH1/EX1.4/ex1_4.sce b/2885/CH1/EX1.4/ex1_4.sce
new file mode 100755
index 000000000..69cbc2dc6
--- /dev/null
+++ b/2885/CH1/EX1.4/ex1_4.sce
@@ -0,0 +1,38 @@
+

+//Find percentage variation in load current and load voltage

+clear;

+clc;

+//soltion

+//given

+Vs=10;//volt//Supply voltage

+Rs=100;//ohm//internal resistance

+

+// In accordance to figure 1.24a

+//For 1Ω - 10 Ω

+Rl11=1;//ohm//min extreme value of Rl

+Rl12=10;//ohm//max extreme value of Rl

+Il11=Vs/(Rs+Rl11);

+Il12=Vs/(Rs+Rl12);

+Pi1=(Il11-Il12)*100/Il11;//Percentage variation in current

+Vl11=Il11*Rl11;

+Vl12=Il12*Rl12;

+Pv1=(Vl12-Vl11)*100/Vl12;//Percentage variation in voltage

+printf("\nIn accordance to figure 1.24a \n");

+printf("Percentage variation in Current(1-10 Ω) %.2f percent\n",Pi1);

+printf("Percentage variation in Voltage(1-10 Ω) %.1f percent\n\n",Pv1);

+

+// In accordance to figure 1.24b

+//For 1kΩ - 10kΩ

+Rl21=1000;//ohm//min extreme value of Rl

+Rl22=10000;//ohm//max extreme value of Rl

+Il21=Vs/(Rs+Rl21);

+Il22=Vs/(Rs+Rl22);

+Pi2=(Il21-Il22)*100/Il21;//Percentage variation in current

+Vl21=Il21*Rl21;

+Vl22=Il22*Rl22;

+Pv2=(Vl22-Vl21)*100/Vl22;//Percentage variation in voltage

+printf("\nIn accordance to figure 1.24b \n");

+printf("Percentage variation in Current(1-10 Ω) %d percent \n",Pi2);

+printf("Percentage variation in Voltage(1-10 Ω) %.1f percent \n\n",Pv2);

+// In book the percentage variation in voltage(1kΩ-10kΩ) is 9 percent due to 

+// the incorrect value of Il22 i.e. 0.000999 Amp correct value is 0.0009901 Amp