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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
commitb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch)
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+//Ex8_6 pg-436
+clc
+
+A=50 //voltage gain
+per=10/100 //percentage of negative feedback applied
+BA=per*A //value of Beta*A
+Af=A/(1+BA) //gain after negative feedback
+printf("(1) Voltage gain after negative feedback \n")
+printf(" = %.2f\n ",Af)
+
+A=50 //voltage gain
+per=5/100 //percentage of negative feedback applied
+BA=per*A //value of Beta*A
+Af1=A/(1+BA) //gain after negative feedback
+printf("(2) Voltage gain after negative feedback \n")
+printf(" = %.1f\n ",Af1)
+disp("So the new gain is not double the previous case")
+disp(" The difference between expected value and actual value of gain obtained is")
+diff_value=2*Af-Af1
+printf(" = %.2f",diff_value)
+
+printf("\n\n(3) To have the gain double of case(1) i.e 16.66,let the \n feedback introduced be Beta(assuming negative feedback)")
+Af=16.66 //voltage gain with negative feedback
+A=50 //voltage gain
+Beta=((A/Af)-1)/A //feedback in percentage
+printf("\n Beta = %.2f",Beta)