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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Ex10_3 Pg-517
+clc
+
+R1=10*10^(3) //resistor R1 in ohm
+Rf=50*10^(3) //feedback resistor in ohm
+Vin=10*10^(-3) //input voltage in V
+Ro=5000 //load resistor in ohm
+
+disp("A'' = Vo/Vi = (-1)*Rf/R1*(1+1/A*(1+Rf/R1))^-1 ")
+A=5000
+Vo=Vin*(Rf/R1)/(1+1/A*(1+Rf/R1)) //output voltage
+printf("\n When gain A=%.0f",A)
+printf(" \n Amplified output voltage = %.1f mV \n",Vo*1e3)
+
+A=10000
+Vo=Vin*(Rf/R1)/(1+1/A*(1+Rf/R1))
+printf("\n When gain A=%.0f",A)
+printf(" \n Amplified output voltage = %.2f mV \n",Vo*1e3)
+
+A=5000
+Rout=Ro/(1+A*R1/Rf) //load resistance
+printf(" \n Ro'' = %.3f ohm \n",Rout)
+
+A=10000
+Rout=Ro/(1+A*R1/Rf) //load resistance
+printf(" \n Ro'' = %.3f ohm \n",Rout)