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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//find the size of the bolts
+clc
+//solution
+//given
+//ref fig 11.35
+W=12000//N
+L=400//mm
+L1=50//mm
+L2=375//mm
+ft=84//N/mm^2
+n=4
+Ws=W/n//shear load on each bolt
+Wt=0.5*[[W*L*L2]/[L1^2 +L2^2]]//N
+Wte=0.5*[Wt + sqrt(Wt^2 +4*(Ws)^2)]//N//equivalent tensile load
+//let dc be core dia
+pi=3.14
+//A=(pi/4)*dc^2*ft=66*dc^2
+dc=sqrt(Wte/66)//mm
+//let tabd b be thickness and depth of arm
+//Z=(1/6)*t*b^2
+M=W*L//N-mm
+Z=M/84//
+//asume b=250
+b=250//mm
+//Z=b^2*t/6
+t=(M*6)/(ft*b^2)
+printf("the value of core diameteris, %f mm\n",dc)
+printf("the standard value of core diametr is 11.546 mm fron T11.1\n")
+printf("the value of equivalent tensile load is,%f N\n",Wte)
+printf("the value tensile load is,%f N\n",Wt)
+printf("the value of load actiung on each bolt is,%f N\n",Ws)
+printf("the moment acting is,%f N-mm\n",M)
+printf("the value of thickness is,%f mm",t) \ No newline at end of file