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authorpriyanka2015-06-24 15:03:17 +0530
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+////find size of weld
+clc
+//solution
+//given
+//ref fig 10.28
+P=15000//N
+T=80//N/mm^2
+b=80//mm
+l=50//mm
+e=125//mm
+//let s be size of weld
+//A=2*t*l//70.7*s//mm^2
+//T1=P/A//N/mm^2//direct stress
+//T1=212/s
+//J=t*l*(3*b^2+l^2)/6//mm^4
+//J=127850*s//mm^4
+ab=40//mm
+bg=25//mm=r1
+r2=(sqrt(ab^2+bg^2))//mm
+printf("the value of r2 is,%f mm\n",r2)
+//T2=P*e*r2/J
+//T2=689.3/s//N/mm^2
+//cos(q)=r1/r2=25/47=0.532
+a=0.532
+//T=sqrt(T1^+T2^2+2*T1*T2*a)
+//80=822/s
+s=822/80//mm
+printf("the sieze of weld is,%f mm",s) \ No newline at end of file