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authorpriyanka2015-06-24 15:03:17 +0530
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+//find max noraml and shear stress
+clc
+//solution
+//given
+//ref fig 10.25
+D=50//mm
+s=15//mm
+P=10000//N
+e=200//mm
+//let t is thickness of throat
+//A=t*pi*D
+pi=3.14
+A=0.707*s*pi*D//mm^2
+t=P/A//N/mm^2
+M=P*e//N-mm
+Z=pi*.707*s*D^2/4//mm^3
+fb=M/Z//N/mm^2
+ftmax=(0.5*fb)+(0.5*sqrt(fb^2+4*t^2))//N/mm^2
+Tmax=(0.5*sqrt(fb^2+4*t^2))//N/mm^2
+printf("the max normal stress and shear stress are,%f N/mm^2\n,%f N/mm^2 respectively",ftmax,Tmax)