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authorpriyanka2015-06-24 15:03:17 +0530
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+//Transport Processes and Seperation Process Principles
+//Chapter 1
+//Example 1.7-2
+//Introduction to engineering principles and units
+//given data: CO + 0.5O2 -> CO2
+//del H (298K)=-282.989*10^3 kJ/kg mol
+//inlet flow rate= 1 kg mol/h=i
+i=1;
+it=0.5*i;// moles of O2 theorettically reqd
+oa=it*(1.9);//moles of O2 actually added
+n=oa*(0.79/0.21);//moles of N2 added
+air=oa+n;
+oout=oa-it;
+// CO2 in outlet flue gas is 1 kg/h and N2 in outlet flue gas=n
+//calculating input enthalpy of diff components from formula H= m*Cp*(delta T) and Cp evaluated from data tables
+Hico=1*29.38*(473-298);
+Hiair=4.520*29.29*(373-298);
+Histd=-(-282.989*(10^3))*(1);
+//calculating output enthalpy of diff components from formula H= m*Cp*(delta T) and Cp evaluated from data tables
+HoCO2=1*49.91*(1273-298);
+HoO2=oout*33.25*(1273-298);
+HN2=n*31.43*(1273-298);
+//Energy in=Energy out ; Hico+Hiair+q(heat added)+Histd=HoCO2+HoO2+HN2
+q=HoCO2+HoO2+HN2-(Hico+Hiair+Histd);
+mprintf("the heat removed in is %f kJ/h",q)
+//end