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+//Transport Processes and Seperation Process Principles
+//Chapter 1
+//Example 1.6-5
+//Introduction to engineering principles and units
+//given data
+//heat of formation at 298K for methane is -74.848x10^3 kJ/kg mol, water is 285.840x10^3 kJ/kg mol ,CO is -110.523x10^3 kJ/kg mol,H2 is 0x10^3 kJ/kg mol
+//basis: 1 kg mol of methane at 101.325 kPa and 298K: CH4 + H20 -> CO+ H2
+//std heat of reaction=(sum of heat of formation of pdts)-(sum of heat of formation of pdts)
+H=(-110.523*10^3-3*0)-(-74.848*10^3-285.840*10^3);
+mprintf("the std heat of reaction in is %f kJ/kgmol",H)
+//end