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authorpriyanka2015-06-24 15:03:17 +0530
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+//Transport Processes and Seperation Process Principles
+//Chapter 1
+//Example 1.6-4
+//Introduction to engineering principles and units
+//given data
+//heat of combustion for carbon to carbon dioxide is -393x10^3 kJ/kg mol or -94.0518 kCal/g mol
+//heat of combustion for carbon to carbon monoxide is -110x10^3 kJ/kg mol or -26.4157 kCal/g mol
+//basis: 10 g bol of carbon where 90% converts to carbon dioxide and rest to carbon monoxide
+HkJ=(90/100)*10*(-393.513)+(10/100)*10*(-110.523);//change in enthalpy= sum of heat of combustion of products(as reactant is a plain element)
+HkCal=(90/100)*10*(-94.0518)+(10/100)*10*(-26.4157);
+mprintf("change in enthalpy %f kJ",HkJ)
+mprintf("change in enthalpy %f kCal",HkCal)
+//end