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+//Transport Processes and Seperation Process Principles

+//Chapter 1

+//Example 1.5-2

+//Introduction to engineering principles and units

+//given data

+//Basis: feed stream is 1000 kg/h

+//component balance for Pottasium Nitrate: 1000(20/100)=W(0)+P(96/100)

+P=1000*(0.2)*(100/96);//P is the outlet rate of KNO3 crystals

+

+//overall balance for a crystallizer: S-R=P

+//KNO3 balance on crystallizer: S(50/100)-R(37.5/100)=P(96/100)

+//solving 2 equations using matrix operations

+A=[1 -1;0.5 -0.375];

+B=[P;0.96*P];

+x=inv(A)*B;

+S=x(1,1);

+R=x(2,1);

+mprintf(" the recycle R %f kg/h",R)

+mprintf("the rate of crystals getting out of crystallizer %f kg/h",S)