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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2705/CH8/EX8.5/Ex8_5.sce | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '2705/CH8/EX8.5/Ex8_5.sce')
| -rwxr-xr-x | 2705/CH8/EX8.5/Ex8_5.sce | 21 |
1 files changed, 21 insertions, 0 deletions
diff --git a/2705/CH8/EX8.5/Ex8_5.sce b/2705/CH8/EX8.5/Ex8_5.sce new file mode 100755 index 000000000..a69209cb1 --- /dev/null +++ b/2705/CH8/EX8.5/Ex8_5.sce @@ -0,0 +1,21 @@ +clear;
+clc;
+disp('Example 8.5');
+
+// aim : To determine
+// the volume of the air required
+
+// Given values
+H2 = .45;// volume fraction of H2
+CO = .40;// volume fraction of CO
+CH4 = .15;// volume fraction of CH4
+
+// solution
+V = 2.38*(H2+CO)+9.52*CH4;// stoichimetric volume of air, [m^3]
+
+mprintf('\n The volume of air required is = %f m^3/m^3 fuel\n',V);
+
+// Result in the book is misprinted
+
+// End
+
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