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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2705/CH8/EX8.22 | |
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initial commit / add all books
Diffstat (limited to '2705/CH8/EX8.22')
| -rwxr-xr-x | 2705/CH8/EX8.22/Ex8_22.sce | 53 |
1 files changed, 53 insertions, 0 deletions
diff --git a/2705/CH8/EX8.22/Ex8_22.sce b/2705/CH8/EX8.22/Ex8_22.sce new file mode 100755 index 000000000..9e5bddbd5 --- /dev/null +++ b/2705/CH8/EX8.22/Ex8_22.sce @@ -0,0 +1,53 @@ +clear;
+clc;
+disp('Example 8.22');
+
+// aim : To determine
+// the percentage gravimetric analysis of the total products of combustion
+
+// given values
+CO = 12;// %age volume composition of CO
+H2 = 41;// %age volume composition of H2
+CH4 = 27;// %age volume composition of CH4
+O2 = 2;// %age volume composition of O2
+CO2 = 3;// %age volume composition of CO2
+N2 = 15;// %age volume composition of N2
+
+mCO2 = 44;// moleculer mass of CO2,[kg/kmol]
+mH2O = 18;// moleculer mass of H2O, [kg/kmol]
+mO2 = 32;// moleculer mass of O2, [kg/kmol]
+mN2 = 28;// moleculer mass of N2, [kg/kmol]
+
+ea = 15;// %age excess air required
+aO2 = 21;// %age air composition in the air
+
+// solution
+// combustion equation by no. of moles
+// 12CO + 41H2 + 27CH4 + 2O2 + 3CO2 + 15N2 + aO2+79/21*aN2 = bCO2 + dH2O + eO2 + 15N2 +79/21*aN2
+// equating C coefficient
+b = 12+27+3;// [mol]
+// equatimg H2 coefficient
+d = 41+2*27;// [mol]
+// O2 required is 15 % extra,so
+// e/(e-a)=.15 so e=.13a
+// equating O2 coefficient
+// 2+3+a=b+d/2 +e
+
+a = (b+d/2-5)/(1-.13);
+e = .13*a;// [mol]
+
+// gravimetric analysis of product
+v1 = b*mCO2;// gravimetric volume of CO2
+v2 = d*mH2O ;// gravimetric volume of H2O
+v3 = e*mO2;// gravimetric volume of O2
+v4 = 15*mN2 +79/21*a*mN2;// gravimetric volume of N2
+
+vt = v1+v2+v3+v4;// total
+x1 = v1/vt*100;// percentage gravimetric of CO2
+x2 = v2/vt*100;// percentage gravimetric of H2O
+x3 = v3/vt*100;// percentage gravimetric of O2
+x4 = v4/vt*100;// percentage gravimetric of N2
+
+mprintf('\n Percentage gravimetric composition of CO2 = %f\n ,\n Percentage gravimetric composition of H2O = %f\n\n Percentage gravimetric composition of O2 = %f\n\n Percentage gravimetric composition of N2 = %f\n',x1,x2,x3,x4);
+
+// End
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