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+// FUNDAMENTALS OF ELECTICAL MACHINES
+// M.A.SALAM
+// NAROSA PUBLISHING HOUSE
+// SECOND EDITION
+
+// Chapter 8 : STARTING, CONTROL AND TESTING OF AN INDUCTION MOTOR
+// Example : 8.5
+
+clc;clear; // clears the console and command history
+
+// Given data
+V = 210 // supply voltage in V
+f = 50 // supply frequency in Hz
+P = 4 // number of poles
+P_0 = 400 // i/p power in W
+I_0 = 1.2 // line current in A
+V_0 = 210 // line voltage
+P_fw = 150 // total friction and windage losses in W
+R = 2.2 // stator resistance between two terminals in ohm
+
+// caclulations
+R_1 = R/2 // per phase stator resistance in ohm
+P_scu = 3*I_0^2*R_1 // copper loss in W
+P_core = P_0-P_fw-P_scu // stator core loss in W
+R_0 = (V_0/sqrt(3))^2/(P_core/3) // no-load resistance in ohm
+// alternate approach
+phi_0 = acosd(P_core/(sqrt(3)*V_0*I_0)) // power factor angle
+X_0 = (V_0/sqrt(3))/(I_0*sind(phi_0)) // magnetizing reactance per phase in ohm
+
+// display the result
+disp("Example 8.6 solution");
+printf(" \n No-load resistance \n R_0 = %.1f ohm \n", R_0 );
+printf(" \n Magnetizing reactance per phase \n X_0 = %.0f ohm \n", X_0 );
+