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authorpriyanka2015-06-24 15:03:17 +0530
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+//Variable declaration:
+LR = 7.5/12.0 //Thickness of refractory (ft)
+kR = 0.75 //Thermal conductivity of refractory
+TR = 2000.0 //Average surface temperature of the inner face of the refractory (°F)
+Q = 450.0 //Heat loss (Btu/h.ft^2)
+
+//Calculation:
+TI = TR - Q*(LR/kR) //Temperature of the boundary where the refractory meets the insulation (°F)
+
+//Result:
+printf("The temperature of the boundary where the refractory meets the insulation is : %.0f °F .",TI)