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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Exa Misc. 6.10
+clc;
+clear;
+close;
+format('v',6)
+// Given data
+R_F = 60;// in ko hm
+R1 = 20;// in k ohm
+Vin1 = 2;// in V
+Vin2 = 0.1;// in V
+// The output voltage, by using super position theorm,
+Vo = ((-R_F/R1)*Vin1) + ((1+(R_F/R1))*Vin2);// in V
+disp(Vo,"The output voltage in V is");