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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clear
+clc
+w2=0.122;//amount of benzoic acid in kg
+w1=1;//amount of benzene in kg
+Tb1=353;//boiling point of benzene in K
+Tb2=354.5;//boiling point at which actually boiling of benzene starts in K
+DelH_v=394.57;//in J/gm
+M1=w2/0.122;//amount of benzoic acid in mol
+R=8.314;//in J/Kmol
+M2=((M1*78*10^-3)*R*Tb1^2*w2)/(w1*(Tb2-Tb1)*(DelH_v*78));//apparant molar mass of benzoic acid in kg/mol
+printf('M2=%.4f kg/mol',M2)
+alpha=2*(1-(w2/M2));//degree of dimerisation in mol
+printf('\nalpha=%.4f mol',alpha)
+
+//There are some errors in the solution given in textbook
+//page 75