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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Exa 6.4
+format('v',6)
+clc;
+clear;
+close;
+// Given data
+A= 1000;
+dA= 100;
+dAbyAf= 0.1/100;
+// dAf/Af = 1/|1+B*A| * dA/A or
+B= (dA-dAbyAf*A)/(dAbyAf*A^2)
+disp(B,"The reverse transmission factor of the feedback networks used is : ");
+Af = A/(1+(B*A));
+disp(Af,"The gain with feed back is");