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+clear ;

+clc;

+// Example 11.3

+printf('Example 11.3\n\n');

+printf('Page No. 314\n\n');

+

+//given

+f = 1;// feed of sodium hydroxide in kg

+v = 0.5;// produed vapour in kg

+A = 30;// in m^2

+T1 = 95;// Temperature of boiling solution in deg C

+U = 3*10^3;// heat transfer coefficent in W/m^2-K

+m = 1;// feed rate in kg/s

+Tf = 70;// Feed temperature in deg C

+h_f = 260*10^3;// Enthalpy of feed in J/kg

+h_b = 355*10^3;// Enthalpy of boiling solution in J/kg

+h_v = 2.67*10^6;// Enthalpy of vapour in J/kg

+P1 = 0.6;// Pressure in vapour space in bar

+

+Q = (v*h_b) + (v*h_v) -(f*h_f);// in W

+printf('The total energy requirement is %.0f W \n',Q)

+

+// As Q = A*U*dT

+dT = Q/(U*A);// in degree celcius

+T2 = dT + T1;// in degree celcius

+//The temperature of the heating steam T2 corresponds to a pressure of 1.4 bar. Dry saturated steam at 1.4 bar has a total enthalpy of 2.69*10^6 J/kg

+//Assuming an isentropic compression of the vapour from 0.6 bar to 1.4 bar, the outlet enthalpy is 2.84*10^6 J/kg

+

+// from steam table

+P2 = 1.4// pressure in bar

+h_s = 2.69*10^6;// enthalpy of dry saturated steam in J/kg

+h_v2 = 2.84*10^6 ;// the outlet enthalpy of vapour in J/kg

+

+W = v*(h_v2 - h_s);// Work in W

+T_E = W + 60*10^3;// in W

+printf('The total energy consumption is %.0f W',T_E)

+

+

+

+