From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 2471/CH11/EX11.3/Ex11_3.sce | 40 ++++++++++++++++++++++++++++++++++++++++
 1 file changed, 40 insertions(+)
 create mode 100755 2471/CH11/EX11.3/Ex11_3.sce

(limited to '2471/CH11/EX11.3')

diff --git a/2471/CH11/EX11.3/Ex11_3.sce b/2471/CH11/EX11.3/Ex11_3.sce
new file mode 100755
index 000000000..d19aa63bf
--- /dev/null
+++ b/2471/CH11/EX11.3/Ex11_3.sce
@@ -0,0 +1,40 @@
+clear ;
+clc;
+// Example 11.3
+printf('Example 11.3\n\n');
+printf('Page No. 314\n\n');
+
+//given
+f = 1;// feed of sodium hydroxide in kg
+v = 0.5;// produed vapour in kg
+A = 30;// in m^2
+T1 = 95;// Temperature of boiling solution in deg C
+U = 3*10^3;// heat transfer coefficent in W/m^2-K
+m = 1;// feed rate in kg/s
+Tf = 70;// Feed temperature in deg C
+h_f = 260*10^3;// Enthalpy of feed in J/kg
+h_b = 355*10^3;// Enthalpy of boiling solution in J/kg
+h_v = 2.67*10^6;// Enthalpy of vapour in J/kg
+P1 = 0.6;// Pressure in vapour space in bar
+
+Q = (v*h_b) + (v*h_v) -(f*h_f);// in W
+printf('The total energy requirement is %.0f W \n',Q)
+
+// As Q = A*U*dT
+dT = Q/(U*A);// in degree celcius
+T2 = dT + T1;// in degree celcius
+//The temperature of the heating steam T2 corresponds to a pressure of 1.4 bar. Dry saturated steam at 1.4 bar has a total enthalpy of 2.69*10^6 J/kg
+//Assuming an isentropic compression of the vapour from 0.6 bar to 1.4 bar, the outlet enthalpy is 2.84*10^6 J/kg
+
+// from steam table
+P2 = 1.4// pressure in bar
+h_s = 2.69*10^6;// enthalpy of dry saturated steam in J/kg
+h_v2 = 2.84*10^6 ;// the outlet enthalpy of vapour in J/kg
+
+W = v*(h_v2 - h_s);// Work in W
+T_E = W + 60*10^3;// in W
+printf('The total energy consumption is %.0f W',T_E)
+
+
+
+
-- 
cgit