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+// Exa 6.36

+format('v',7);clc;clear;close;

+// Given data

+C2 = 500;// capacitance in nF

+C2 = C2 * 10^-9;// in F

+f = 50;//frequency in Hz

+omega = 2*%pi*f;// in rad/sec

+C4 = 0.148;//capacitance in µF

+C4 = C4 * 10^-6;// in F

+R4 = 72.6;//resistance in ohm

+R3 = 300;//resistance in ohm

+C1 = C2*(R4/R3);// capacitance in F

+C1 = C1 * 10^6;// in µF

+disp(C1,"The capacitance in µF is");

+delta = atand(omega*C4*R4);//dielectric loss angle of capacitance in degree

+disp(delta,"The dielectric loss angle of capacitance in degree is");

+

+// Note: The calculation in the book is wrong, so the answer in the book is wrong.