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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Exa 5.14.10
+clc;
+clear;
+close;
+// Given data
+V_ECsat= 0.2;// in V
+V_CC= 10;// in V
+V_EBsat= 0.8;// in V
+
+// Part (i)
+bita= 100;
+R_B= 220;// in kΩ
+// Applying KVL to collector circuit, V_CC= V_EC+ICRC
+ICRC= V_CC-V_ECsat;// in V
+// Applying KVL to input loop, V_CC= V_EBsat+I_B*R_B (i)
+I_B= (V_CC-V_EBsat)/R_B;// in mA
+I_C= bita*I_B;// in mA
+R_Cmin= ICRC/I_C;// in kΩ
+disp(R_Cmin,"The minimum value of R_C in kΩ is : ")
+// Part (ii)
+R_C= 1.2;// in kΩ
+I_Csat= ICRC/R_C;// in mA
+I_B= I_Csat/bita;// in mA
+// From eq (i)
+R_B= (V_CC-V_EBsat)/I_B;// in kΩ
+disp(R_B,"The maximum value of R_B in kΩ is : ")
+