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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2240/CH26/EX25.7/EX25_7.sce | |
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initial commit / add all books
Diffstat (limited to '2240/CH26/EX25.7/EX25_7.sce')
| -rwxr-xr-x | 2240/CH26/EX25.7/EX25_7.sce | 21 |
1 files changed, 21 insertions, 0 deletions
diff --git a/2240/CH26/EX25.7/EX25_7.sce b/2240/CH26/EX25.7/EX25_7.sce new file mode 100755 index 000000000..7a3056cc7 --- /dev/null +++ b/2240/CH26/EX25.7/EX25_7.sce @@ -0,0 +1,21 @@ +// Grob's Basic Electronics 11e
+// Chapter No. 25
+// Example No. 25_7
+clc; clear;
+// In Fig. 25–9, assume that with a 4-mVac input signal for VT, the voltage across R1 is 2 mV when R1 is 225-kOhms. Determine Zeq and Q.
+
+// Given data
+
+vin = 4*10^-3; // Input AC signal=4 mVac
+R1 = 225*10^3; // Resistance1=225 kOhms
+vR1 = 2*10^-3; // Voltage across Resistor1=2 mVac
+xl = 1.5*10^3; // Inductive Reactance=1.5 kOhms
+
+disp ('Because they divide Vt equally')
+
+Zeq = R1;
+disp (Zeq,'The Equivalent Impedence in Ohms')
+disp ('i.e 225 kOhms')
+
+Q = Zeq/xl;
+disp (Q,'The Q is')
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