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+// Grob's Basic Electronics 11e

+// Chapter No. 23

+// Example No. 23_2

+clc; clear;

+// The following branch currents are supplied from a 50-mV source: Ir=1.8 mA; Il=2.8 mA; Ic=1 mA. Calculate It, Zeq, and Theta I.

+

+// Given data

+

+Va = 50*10^-3;      // Applied voltage=50m Volts

+Ir = 1.8*10^-3;     // Ir=1.8 mAmps

+Il = 2.8*10^-3;     // Ir=2.8 mAmps

+Ic = 1*10^-3;       // Ic=1 mAmps

+

+nI = Il-Ic;         // net current

+Ir1 = Ir*Ir;

+nI1 = nI*nI;

+

+It = sqrt(Ir1+nI1);

+disp (It,'The Total Current It in Amps')

+disp ('i.e 2.55 mAmps')

+

+Zeq = Va/It;

+disp (Zeq,'The Equivqlent Impedence Zeq in Ohms')

+disp ('Appox 19.61 Ohms')

+

+Oz = atand(-(nI/Ir));

+disp (Oz, 'Theta z in Degree');