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+// Grob's Basic Electronics 11e
+// Chapter No. 23
+// Example No. 23_2
+clc; clear;
+// The following branch currents are supplied from a 50-mV source: Ir=1.8 mA; Il=2.8 mA; Ic=1 mA. Calculate It, Zeq, and Theta I.
+
+// Given data
+
+Va = 50*10^-3;      // Applied voltage=50m Volts
+Ir = 1.8*10^-3;     // Ir=1.8 mAmps
+Il = 2.8*10^-3;     // Ir=2.8 mAmps
+Ic = 1*10^-3;       // Ic=1 mAmps
+
+nI = Il-Ic;         // net current
+Ir1 = Ir*Ir;
+nI1 = nI*nI;
+
+It = sqrt(Ir1+nI1);
+disp (It,'The Total Current It in Amps')
+disp ('i.e 2.55 mAmps')
+
+Zeq = Va/It;
+disp (Zeq,'The Equivqlent Impedence Zeq in Ohms')
+disp ('Appox 19.61 Ohms')
+
+Oz = atand(-(nI/Ir));
+disp (Oz, 'Theta z in Degree');