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authorpriyanka2015-06-24 15:03:17 +0530
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+//Example 2_18
+clc;
+clear;close;
+
+//Given data:
+Vs=400;//V
+f=50;//Hz
+Idc=150;//A
+alfa=60;//degree
+
+//Solution :
+Vm=Vs*sqrt(2)/sqrt(3);//V
+Vdc=3*sqrt(3)/%pi*Vm*cosd(alfa)//V
+Pdc=Vdc*Idc;//W
+disp(Pdc,"Output power, Pdc(W)");
+Iavg=Idc/3;//A
+disp(Iavg,"Average thyristor current(A)");
+Irms=Idc/sqrt(3);//A
+disp(Irms,"RMS value of thyristor current(A)");
+Ipeak=Idc;//A
+disp(Ipeak,"Peak current through thyristor(A)");
+PIV=sqrt(2)*Vs;//V
+disp(PIV,"Peak inverse voltage(V)");
+//Answer of first part in the book is wrong.