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+clc

+//Example 11.1

+//Calculate the powerr absorbed by capacitor and resistor

+printf("Given")

+disp('Capacitor 5uF, Resistor 200 ohm, Voltage source is 40+60*u(t)')

+C=5*10^-6;R=200;

+//For t<0 the value of u(t) is zero hence at t=0- the value of voltage is 40V

+//For t=0+ the voltage is 100V 

+//At t=0+ the capacitor cannot charge instantaneously hence resistor voltage is 60V

+disp('For t=0+')

+VR=60;

+i0=VR/R

+T=R*C

+t=1.2*10^-3

+disp('The value of current is i(t)=i0*exp(-t/T)')

+ival=i0*exp(-t/T)

+printf("Value of resistor current at 1.2ms=%3.2f mA \n",ival*10^3)

+//Let PR be the power absorbed by the resistor

+PR=ival^2*R

+printf("Value of resistive power at 1.2ms=%3.2f W \n",PR)

+//Out of the 100V available at t>0 the voltage across the capacitor is

+disp('vC(t)=100-60*exp(-t/T)')

+vCval=100-60*exp(-t/T)

+printf("Value of capacitor voltage at 1.2ms=%3.2f V \n",vCval)

+//Let PC be the power absorbed by the capacitor

+PC=ival*vCval

+printf("Value of capacitive power at 1.2ms=%3.2f W \n",PC)
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