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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /213/CH16/EX16.15/16_15.sce | |
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initial commit / add all books
Diffstat (limited to '213/CH16/EX16.15/16_15.sce')
| -rwxr-xr-x | 213/CH16/EX16.15/16_15.sce | 30 |
1 files changed, 30 insertions, 0 deletions
diff --git a/213/CH16/EX16.15/16_15.sce b/213/CH16/EX16.15/16_15.sce new file mode 100755 index 000000000..52732a0de --- /dev/null +++ b/213/CH16/EX16.15/16_15.sce @@ -0,0 +1,30 @@ +//To find mass and cross section
+clc
+//Given:
+P=150*1000 //W
+N=80 //rpm
+CE=0.1
+D=2, R=D/2 //m
+rho=7200 //kg/m^3
+//Solution:
+//Calculating the angular speed of the engine
+omega=2*%pi*N/60 //rad/s
+//Calculating the coefficient of fluctuation of speed
+CS=4/100
+//Mass of the flywheel rim:
+//Calculating the work done per cycle
+WD=P*60/N //Work done per cycle, N-m
+//Calculating the maximum fluctuation of energy
+deltaE=WD*CE //N-m
+//Calculating the mass moment of inertia of the flywheel
+I=deltaE/(omega^2*CS) //kg-m^2
+//Calculating the mass moment of inertia of the flywheel rim
+Irim=0.95*I //kg-m^2
+//Calculating the mass of the flywheel rim
+k=R //Radius of gyration, m
+m=Irim/k^2 //kg
+//Calculating the cross-sectional area of the flywheel rim
+A=m/(2*%pi*R*rho) //m^2
+//Resilts:
+printf("\n\n Mass of the flywheel rim, m = %d kg.\n\n",m)
+printf(" Cross-sectional area of the flywheel rim, A = %.3f m^2.\n\n",A)
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