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+// Exa 7.2

+clc;

+clear;

+close;

+// Given data

+bita= 100;

+R1= 1;// in kΩ

+R1= R1*10^3;//in Ω

+R2= 300;// in Ω

+R3= 360;// in Ω

+R4= 640;// in Ω

+V1= 10;// in V

+V2= 20;// in V

+I_B1=19.2*10^-3;// in A

+I_L= 1;//in A

+V_Z= 5.6;// in V

+V_B= R4*V1/(R3+R4);//in V

+V_BE2= V_B-V_Z;// in V

+V_A= V1-V_BE2;// in V

+disp(V_A,"The value of V_A in volt is : ")

+disp(V_B,"The value of V_B in volt is : ")

+

+// Part (ii)

+I1= V1/(R3+R4);// in A

+//I1= .01*10^-3;// in A

+I2= (V2-V_A)/R2;// in A

+I_C2= I2-I_B1;// in A

+I_B1= (I1+I_L)/(1+bita);// in A

+disp(I_B1*10^3,"The base current of T1 in mA is : ")

+I_C2= I2-I_B1;// in A

+I_E2= I_C2;// in A

+disp(I_E2*10^3,"The emitter current of T2 in mA is : ")

+

+// part (iii)

+I3= (V2-V_Z)/R1;// in A

+I_Z= I3+I_E2;// in A

+disp(I_Z*10^3,"Current through zener diode in mA is : ")

+V_CE= V2-V1;// in V

+I_C1= bita*I_B1;// in A

+T1= V_CE*I_C1;// in W

+disp(T1,"Power dissipation in watt is : ")

+

+// Note: In the part (iv), the wrong value of I_B1 and bita is putted, these two value is putted of the Example 7.1

+//          (i.e. I_B1= 19.8 mA and bita= 50) whereas in this example the value of bita is given 100 and the value of 

+//          of I_B1 is calculated as 10 mA. So the answer of the last part of this example is wrong.

+

+

+

+

+

+