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authorpriyanka2015-06-24 15:03:17 +0530
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+// Exa 2.20
+clc;
+clear;
+close;
+// Given data
+N_D= 5*10^22/10^8;
+q=1.6*10^-19;// in C
+ni= 1.45*10^10;// per m^3
+miu_n= 1300;// in m^2/Vs
+// n*p= ni^2 or N_D*p = ni^2
+p= ni^2/N_D;// in /cm^3
+sigma= q*miu_n*N_D;// in (Ωcm)^-1
+rho= 1/sigma;//in Ωcm
+disp(rho,"Resistivity in Ωcm is : ")