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authorpriyanka2015-06-24 15:03:17 +0530
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+//Example 1.59://READING
+clc;
+clear;
+q=[5.30,5.73,6.77,5.26,4.33,5.45,6.09,5.64,5.81,5.75];//length in mm
+AM= mean(q);//arithematic mean in mm
+for i= 1:10
+ qb(i)= q(i)-AM;
+end
+Q= [qb(1),qb(2),qb(3),qb(4),qb(5),qb(6),qb(7),qb(8),qb(9),qb(10)];//
+AV=(-qb(1)-qb(2)+qb(3)+qb(4)-qb(5)-qb(6)+qb(7)+qb(8)-qb(9)+qb(10))/10;//
+SD=st_deviation(Q);//standard deviation
+for i=1:10
+ B(i)= (qb(i))/SD;//
+ disp(B(i))
+end
+V=SD^2;//variance
+disp(AM,"arithematic mean in mm")
+disp(SD,"standard deviation in mm")
+disp("it is given that for 10 readings the ratio of deviation to standard deviation is not to exceed 1.96 and therefore reading no. 5 i.e. 4.33m should be rejected")
+