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authorpriyanka2015-06-24 15:03:17 +0530
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+clc;
+m=1.5; // Mass of the fluid in kg
+p1=1.6; // Initial pressure of fluid in MPa
+T1=250; // Initial temperture of fluid in degree celcius
+p2=150; // Initial pressure of the fluid in kPa
+n=1.25; // Index of polytropic process
+// (a).Steam
+// Following are the values taken from steam table
+// state 1 is superheated
+u1=2692.3; // specific internal energy in kJ/kg
+s1=6.6732; // specific entropy in kJ/kg K
+v1=0.14184; // specific volume of the steam in m^3/kg
+v2=v1*(p1/(p2*10^-3))^(1/n); // specific volume of the steam at state 2
+// State 2 is wet
+T2=111.37; // Final temperature of steam in degree celcius
+vf2=0.0010531; vfg2=1.1582; // specific volume of the steam in m^3/kg
+x2=(v2-vf2)/vfg2; // Quality of steam at state 2
+sf2=1.4336; sfg2=5.7897; // specific entropy in kJ/kg K
+uf2=466.94; ufg2=2052.7; // specific internal energy in kJ/kg
+s2=sf2+x2*sfg2; // specific entropy in kJ/kg K
+u2=uf2+x2*ufg2; // specific internal energy in kJ/kg
+W=m*((p2*v2)-(p1*10^3*v1))/(1-n); // Work done
+Q=m*(u2-u1)+W; // Heat ttransferred
+S21=m*(s2-s1); // Change in entropy
+disp ("kJ",Q,"Heat transferred = ","kJ",W,"Work done = ","kJ/K",S21,"Change in entropy = ","K",T2+273,"Final Temperature = ","(a).Steam");
+// (b).Air
+R=0.287; // characteristic gas constant of air in kJ/kg K
+Cvo=0.7165; // Specific heat at constant volume in kJ/kg K
+T2=(T1+273)*((p2*10^-3)/p1)^((n-1)/n); // Final temperature of air
+W=m*R*(T2-(T1+273))/(1-n); // Work done
+Q=m*Cvo*(T2-(T1+273))+W; // Heat transferred
+S21=m*(Cvo+R/(1-n))*log (T2/(T1+273)); // Change in entropy
+disp ("kJ",Q,"Heat transferred = ","kJ",W,"Work done = ","kJ/K",S21,"Change in entropy = ","K",T2,"Final Temperature = ","(b).Air");