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authorpriyanka2015-06-24 15:03:17 +0530
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+clc;
+m=1.5; // Mass of the fluid in kg
+p1=1.6; // Initial pressure of fluid in MPa
+T1=250; // Initial temperture of fluid in degree celcius
+p2=150; // Initial pressure of the fluid in kPa
+// (a).Steam
+// Following are the values taken from steam table
+// state 1 is superheated
+u1=2692.3; // specific internal energy in kJ/kg
+s1=6.6732; // specific entropy in kJ/kg K
+v1=0.14184; // specific volume of the steam in m^3/kg
+// State 2 is wet (s1=s2<sg2)
+T2=111.37; // Final temperature of steam in degree celcius
+sf2=1.4336; sfg2=5.7897; // specific entropy in kJ/kg K
+uf2=466.94; ufg2=2052.7; // specific internal energy in kJ/kg
+x2=(s1-sf2)/sfg2; // Quality of steam at state 2
+u2=uf2+x2*ufg2; // specific internal energy in kJ/kg
+W=-m*(u2-u1);// Work done
+disp ("kJ",W,"Work done = ","K",T2+273,"Final temperature of steam =","(a).Steam");
+// (b).Air
+Cvo=0.7165; // Specific heat at constant volume in kJ/kg K
+k=1.4; // index of reversible adiabatic process
+T2=(T1+273)*((p2*10^-3)/p1)^((k-1)/k); // Final temperature of air
+W=-m*Cvo*(T2-(T1+273)); // Work done
+disp ("kJ",W,"Work done = ","K",T2,"Final temperature of =","(b).Air");