initial commit / add all books

14 files changed, 163 insertions, 0 deletions

diff --git a/1991/CH6/EX6.1/1.sce b/1991/CH6/EX6.1/1.sce
new file mode 100755
index 000000000..4bb82886c
--- /dev/null
+++ b/1991/CH6/EX6.1/1.sce
@@ -0,0 +1,11 @@
+clc

+clear

+//input

+m=0.5 //mass

+c=460 //specific heat capacity of iron

+t1=70//initial temperature

+t2=10//final temperature

+//calculation

+q=m*c*(t1-t2)//heat required 

+//output

+printf("the heat required is %3.0f J",q)

diff --git a/1991/CH6/EX6.10/10.sce b/1991/CH6/EX6.10/10.sce
new file mode 100755
index 000000000..7bc0e0070
--- /dev/null
+++ b/1991/CH6/EX6.10/10.sce
@@ -0,0 +1,13 @@
+clc

+clear

+//input

+m=3*10^-2 //mass of water

+r1=1*10^3//density of water

+r2=0.5//density of steam

+p=1.01*10^5//atmospheric pressure

+//calculation

+v1=m/r1//volume of water

+v2=m/r2//volume of gas

+w=(v2-v1)*p//external work done by gas

+//output

+printf("the work done is %3.0f J",w)

diff --git a/1991/CH6/EX6.12/12.sce b/1991/CH6/EX6.12/12.sce
new file mode 100755
index 000000000..9f1b9d35b
--- /dev/null
+++ b/1991/CH6/EX6.12/12.sce
@@ -0,0 +1,10 @@
+clc

+clear

+//input

+r100=6.9//resistence of steam

+r0=5.8 //resistece of ice

+t=550 //temperature

+//calculation

+r=(t*(r100-r0))/100 +5.8//platinum resistance thermometre

+//output

+printf("the resistence is %3.3f ohm",r)

diff --git a/1991/CH6/EX6.14/14.sce b/1991/CH6/EX6.14/14.sce
new file mode 100755
index 000000000..912bc1cc4
--- /dev/null
+++ b/1991/CH6/EX6.14/14.sce
@@ -0,0 +1,9 @@
+clc

+clear

+//input

+l=11.7//length of thermometer at steam

+l0=3.4*10^-2//length of thermometer at ice

+//calculation

+x=0.034+0.034*(0.244*10^-3*45^2)//length of temperature on standard scale

+//output

+printf("thread length is %3.3f m",x)

diff --git a/1991/CH6/EX6.15/15.sce b/1991/CH6/EX6.15/15.sce
new file mode 100755
index 000000000..cc0aec62d
--- /dev/null
+++ b/1991/CH6/EX6.15/15.sce
@@ -0,0 +1,11 @@
+clc

+clear

+//input

+a=5 //area

+k=0.07 //thermal conductivity

+dt=21 //temperature difference

+x= 4*10^-3 //thickness of wood

+//calculation

+y=-(k*a*dt/x)//steady state equation

+//output

+printf("the rate of transfer is %3.3f Js^-1",y)

diff --git a/1991/CH6/EX6.16/16.sce b/1991/CH6/EX6.16/16.sce
new file mode 100755
index 000000000..1d224c8c6
--- /dev/null
+++ b/1991/CH6/EX6.16/16.sce
@@ -0,0 +1,11 @@
+clc

+clear

+//input

+d=3*10^-3//thickness of sheet

+l=12*10^-3//seperated distance

+//calculation

+x=1/40//law of conservation of energy

+y=x*d/l//from x

+//output

+printf("the ratio of temperature gradient in rubber to polystyrene is %3.3f0",x)

+printf("\nthe ratio of temperature difference across rubber and polystyrene is %3.3e",y)

diff --git a/1991/CH6/EX6.2/2.sce b/1991/CH6/EX6.2/2.sce
new file mode 100755
index 000000000..f17479e56
--- /dev/null
+++ b/1991/CH6/EX6.2/2.sce
@@ -0,0 +1,14 @@
+clc

+clear

+//input

+T=100 //rise in temperature

+i=2.7 //current

+t=950 //time taken

+mc=0.15//mass of calorimeter 

+cy=3*10^3//specific heat capacity of y

+cc=2*10^3//specific heat capacity of calorimeter

+my=160*10^-3//mass of liquid

+//calculation

+v=((my*cy)+(mc*cc))*T/(i*t)//law of conservation of heat

+//output

+printf("the potential difference is %3.0f V",v)

diff --git a/1991/CH6/EX6.3/3.sce b/1991/CH6/EX6.3/3.sce
new file mode 100755
index 000000000..1107a1c78
--- /dev/null
+++ b/1991/CH6/EX6.3/3.sce
@@ -0,0 +1,16 @@
+clc

+clear

+//input

+iw=4.5 //current

+vw=5.2 //pd of water

+mw=6*10^-2 //flow of water

+cw=4.18*10^3 //heat capacity of water

+ix=5.5//current of x

+iv=7.7//pd of x

+im=18*10^-2//flow of x

+//calculation

+x=(iw*vw)-((mw*cw*5)/60)//rate of heat loss

+cx=(6*4180)/18 +1263//specific heat capacity of x

+//output

+printf("the rate of heat loss is %3.3f W",x)

+printf("\n the specific heat of x is %3.3e Jkg^-1K^-1",cx)

diff --git a/1991/CH6/EX6.4/4.sce b/1991/CH6/EX6.4/4.sce
new file mode 100755
index 000000000..6e582cc2f
--- /dev/null
+++ b/1991/CH6/EX6.4/4.sce
@@ -0,0 +1,10 @@
+ clc

+clear

+//input

+v1=0.52 //volume of ideal gas

+p1=2.3*10^5 //pressure of ideal gas

+p2=6.7*10^5 //pressure changed

+//calculation

+v2=p1*v1/p2//boyle's law

+//output

+printf("the volume is %3.3f m^3",v2)

diff --git a/1991/CH6/EX6.5/5.sce b/1991/CH6/EX6.5/5.sce
new file mode 100755
index 000000000..5872f6be5
--- /dev/null
+++ b/1991/CH6/EX6.5/5.sce
@@ -0,0 +1,10 @@
+clc

+clear

+//input

+v2=11.3 //final volume

+v1=7.8//initial volume

+t1=67+273 //initial temperature

+//calculation

+t2=v2*t1/v1//charles law

+//output

+printf("the final temperature is %3.0d K",t2)

diff --git a/1991/CH6/EX6.6/6.sce b/1991/CH6/EX6.6/6.sce
new file mode 100755
index 000000000..7d6de3bff
--- /dev/null
+++ b/1991/CH6/EX6.6/6.sce
@@ -0,0 +1,12 @@
+clc

+clear

+//input

+p1=1.01*10^5//initial pressure

+t2=135+273//final temperature

+t1=273//initial temperature

+d=2.8 //density

+//calculation

+p2=p1*t2/t1//pressure law

+p=(3*p2/2.8)^0.5//kinetic theory

+//output

+printf("rms speed of gas molecule is %3.0f m/s",p)

diff --git a/1991/CH6/EX6.7/7.sce b/1991/CH6/EX6.7/7.sce
new file mode 100755
index 000000000..31afa41d4
--- /dev/null
+++ b/1991/CH6/EX6.7/7.sce
@@ -0,0 +1,11 @@
+clc

+clear

+//input

+t1=273//initial tenperature

+t2=408//final temperature

+//calculation

+e=t1/t2//ratio of mean molecuar KE

+c1=402*sqrt(0.67)//rms speed

+//output

+printf("the ratio of kinetic energy is %3.3f",e)

+printf("\n  the rms speed of gas molecule is %3.0f ms^-1",c1)

diff --git a/1991/CH6/EX6.8/8.sce b/1991/CH6/EX6.8/8.sce
new file mode 100755
index 000000000..365c126af
--- /dev/null
+++ b/1991/CH6/EX6.8/8.sce
@@ -0,0 +1,15 @@
+clc

+clear

+//input

+p=1.01*10^7 //pressure of gas

+v=0.1 //volume of gas

+R=8.3

+T=280//temperature

+g=0.017//mass of 1 mole

+d=1100//density

+//calculation

+n=p*v/(R*T)//ideal gas equation

+m=n*g//mass of gas

+v=m/d//volume occupied

+//output

+printf("the volume is %3.3e m^3",v)

diff --git a/1991/CH6/EX6.9/9.sce b/1991/CH6/EX6.9/9.sce
new file mode 100755
index 000000000..ba1390392
--- /dev/null
+++ b/1991/CH6/EX6.9/9.sce
@@ -0,0 +1,10 @@
+clc

+clear

+//input

+p1=9*10^4//total pressure

+x=1*10^4//water pressure

+//calculation

+p2=(p1-x)/2//boyles law

+p=p2+x//adding vapour pressure

+//output

+printf("the final pressure is %3.0e Pa",p)