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+//chapter-4 page 149 example 4.12
+//==============================================================================
+clc;
+clear;
+
+//For an air filled circular Waveguide in the dominant mode
+D=4;//Inner diameter of an air filled circular Waveguide in cm
+c=3*10^10;//Velocity of Light in cm/sec
+
+//CALCULATION
+disp('The dominant mode in the circular waveguide would be like TE11,wc is maximum');
+r=D/2;//radius in cm
+wc=((2*(%pi)*r)/1.841);//Cutoff wavelength in cms
+fc=(c/wc)/10^9;//Cutoff frequency in GHz
+mprintf('\nCutoff wavelength is wc=%1.4f cms \nCutoff frequency is fc=%1.3f GHz',wc,fc);
+disp('Since cut-off frequency is 4.395 GHz,frequencies higher than fc will be propagated.Assume a signal of frequency of 5 GHz is being propagated');
+f=5*10^9;//frequency of signal in Hz
+w0=(c/f);//free space wavelength in cm
+wg=(w0/sqrt(1-(w0/wc)^2));//Guide wavelength in cm
+mprintf('\nWave length in the guide is wg=%2.2f cm',wg);
+
+//=========================END OF PROGRAM===============================