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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Scilab code Exa11 : : Page 180 (2011)
+E = 4e+06; // Energy lost in the scintillator, eV
+N_pe = E/10^2*0.5*0.1; // Number of photoelectrons emitted
+G = 10^6; // Gain
+e = 1.6e-019; // Charge of the electron, C
+Q = N_pe*G*e; // Charge collected at the anode of photo multiplier tube, C
+printf("\nCharge collected at the anode of photo multiplier tube : %6.4e C",Q);
+// Result
+// Charge collected at the anode of photo multiplier tube : 3.2000e-010 C \ No newline at end of file