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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Scilab code Exa13.2 : : Page-600 (2011)
+clc; clear;
+E = 200*1.6e-13; // Energy released per fission, joules per neutron
+t = 10^-3; // Time, sec
+P = E/t; // Power produced by one free neutron, watt per neutron
+P_l = 10^9; // Power level, watt
+N = P_l/P; // Number of free neutrons in the reactor, neutrons
+printf("\nThe number of free neutrons in the reactor = %5.3e neutrons", N);
+
+// Result
+// The number of free neutrons in the reactor = 3.125e+016 neutrons \ No newline at end of file