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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//To determine the substation parameters for various Load densities
+//Page 208
+clc;
+clear;
+
+D=[500,500,2000,2000,10000,10000,2000,2000]; //Load Densities in kVA/sq.miles
+TAn=[6,6,3,3,1,1,15,15]; //Substation Area in sq.miles
+VD=[3,6,3,6,3,6,3,6]; //Maximum Total Primary Feeder Voltage drops in percentage
+Vll=[4.16,4.16,4.16,4.16,4.16,4.16,13.2,13.2]; //Base Feeder Voltage in kV
+
+TSn=D.*TAn; //Susbstation Load
+//From the Graphs of feeders vs load desity in the textbook; The Number of feeders are found to be
+
+n=[4,2,5,3,5,4,6,5]; //No of feeders
+
+//Also from the graph, The characteristic or the feeder is determined
+//1-5, 7 are VDL feeders
+//6 and 8 are TL feeders
+
+Sn=TSn./n; //Load Per Feeder
+//To Determine the Load Current
+Il=Sn./(sqrt(3).*Vll);
+
+printf('\na)')
+printf('\nThe Substation Size is\n')
+disp(TSn)
+printf('\nThe Number of Feeders from the Curve is\n')
+disp(n)
+printf('\nAlso From the Curve, 1,2,3,4,5,7 cases are VDL but 6 and 8 case are TL\n')
+printf('\na)')
+printf('\nThe Load Current for 6th Case is %g A, which is less than the ampacities of the main but \nmore than that of the lateral, Hence it is thermally limited but not the main feeder\n',Il(6))
+printf('\nThe Load Current for 8th Case is %g A, which is less than the ampacities of the main but \nmore than that of the lateral, Hence it is thermally limited but not the main feeder\n',Il(8))