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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1835/CH3/EX3.2/Ex3_2.sce | |
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initial commit / add all books
Diffstat (limited to '1835/CH3/EX3.2/Ex3_2.sce')
| -rwxr-xr-x | 1835/CH3/EX3.2/Ex3_2.sce | 28 |
1 files changed, 28 insertions, 0 deletions
diff --git a/1835/CH3/EX3.2/Ex3_2.sce b/1835/CH3/EX3.2/Ex3_2.sce new file mode 100755 index 000000000..7ec2da671 --- /dev/null +++ b/1835/CH3/EX3.2/Ex3_2.sce @@ -0,0 +1,28 @@ +//CHAPTER 3 ILLUSRTATION 2 PAGE NO 103
+//TITLE:FRICTION
+//FIRURE 3.17
+clc
+clear
+//===========================================================================================
+//INPUT DATA
+THETA=45// ANGLE OF INCLINATION IN DEGREES
+g=9.81// ACCELERATION DUE TO GRAVITY IN N/mm^2
+U=.1// COEFFICIENT FRICTION
+//Rn=NORMAL REACTION
+//M=MASS IN NEWTONS
+//f=ACCELERATION OF THE BODY
+u=0// INITIAL VELOCITY
+V=10// FINAL VELOCITY IN m/s^2
+//===========================================================================================
+//CALCULATION
+//CONSIDER THE EQUILIBRIUM OF FORCES PERPENDICULAR TO THE PLANE
+//Rn=Mgcos(THETA)
+//CONSIDER THE EQUILIBRIUM OF FORCES ALONG THE PLANE
+//Mgsin(THETA)-U*Rn=M*f.............BY SOLVING THESE 2 EQUATIONS
+f=g*sind(THETA)-U*g*cosd(THETA)
+s=(V^2-u^2)/(2*f)// DISTANCE ALONG THE PLANE IN metres
+//==============================================================================================
+//OUTPUT
+printf('DISTANCE ALONG THE INCLINED PLANE=%3.3f m',s)
+
+
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