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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1823/CH9 | |
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initial commit / add all books
Diffstat (limited to '1823/CH9')
-rwxr-xr-x | 1823/CH9/EX9.12/SolEx9_12.sce | 8 | ||||
-rwxr-xr-x | 1823/CH9/EX9.2/SolEx9_2.sce | 10 | ||||
-rwxr-xr-x | 1823/CH9/EX9.25/SolEx9_25.sce | 9 | ||||
-rwxr-xr-x | 1823/CH9/EX9.9/SolEx9_9.sce | 10 |
4 files changed, 37 insertions, 0 deletions
diff --git a/1823/CH9/EX9.12/SolEx9_12.sce b/1823/CH9/EX9.12/SolEx9_12.sce new file mode 100755 index 000000000..6e8a5455d --- /dev/null +++ b/1823/CH9/EX9.12/SolEx9_12.sce @@ -0,0 +1,8 @@ +
+//Example 9.12 page no 274
+clear
+clc
+R=10*10^3 //Ω
+f=100 //Hz
+C=(0.1/(2*%pi*f*R))*10^9 //Capicitor
+printf("\n The value of C=%0.3f nF",C)
diff --git a/1823/CH9/EX9.2/SolEx9_2.sce b/1823/CH9/EX9.2/SolEx9_2.sce new file mode 100755 index 000000000..1f2770420 --- /dev/null +++ b/1823/CH9/EX9.2/SolEx9_2.sce @@ -0,0 +1,10 @@ +//derive an exact formula for the gain of a practical inverting op amp.
+//Example 9.2 page no 268
+clear
+clc
+Aol=-10^4
+Rl=1 //kΩ
+Rf=10 //kΩ
+Rd=1 //kΩ
+Av=(Aol/(1+(Rl/Rf)*(1-Aol)+(Rl/Rd)))
+printf("\n The value of Av=%0.3f ",Av)
diff --git a/1823/CH9/EX9.25/SolEx9_25.sce b/1823/CH9/EX9.25/SolEx9_25.sce new file mode 100755 index 000000000..f0e211845 --- /dev/null +++ b/1823/CH9/EX9.25/SolEx9_25.sce @@ -0,0 +1,9 @@ +//Use SPICE methods to simulate this amplifier
+//Example 9.25 page no 281
+clear
+clc
+R1=10*10^3 //Ω
+R2=20*10^3 //Ω
+R3=20*10^3 //Ω
+Av=-((R2*R3)/(R1*(R2+R3)))
+printf("\n The value of Av=%0.3f ",Av)
diff --git a/1823/CH9/EX9.9/SolEx9_9.sce b/1823/CH9/EX9.9/SolEx9_9.sce new file mode 100755 index 000000000..0e828d875 --- /dev/null +++ b/1823/CH9/EX9.9/SolEx9_9.sce @@ -0,0 +1,10 @@ +//Find the regulated output vo in terms of VZ. (b) Given a specific Zener diode and the values of RS and R1
+//Example 9.9 page no 272
+clear
+clc
+Aol=-10^4
+Rl=1
+Rf=10
+Rd=1
+Av=(Aol/(1+(Rl/Rf)*(1-Aol)+(Rl/Rd)))
+printf("\n The value of Av=%0.3f ",Av)
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