1823/CH9/EX9.12/SolEx9_12.sce


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//Example 9.12 page no 274
clear
clc
R=10*10^3   //Ω
f=100       //Hz
C=(0.1/(2*%pi*f*R))*10^9         //Capicitor
printf("\n The value of C=%0.3f  nF",C)