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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /181/CH8/EX8.4/example8_4.sce | |
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initial commit / add all books
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| -rwxr-xr-x | 181/CH8/EX8.4/example8_4.sce | 28 |
1 files changed, 28 insertions, 0 deletions
diff --git a/181/CH8/EX8.4/example8_4.sce b/181/CH8/EX8.4/example8_4.sce new file mode 100755 index 000000000..f18357eb8 --- /dev/null +++ b/181/CH8/EX8.4/example8_4.sce @@ -0,0 +1,28 @@ +// To calculate required Gate source Resistance
+// Basic Electronics
+// By Debashis De
+// First Edition, 2010
+// Dorling Kindersley Pvt. Ltd. India
+// Example 8-4 in page 378
+
+clear; clc; close;
+
+// Given Data
+P=0.012; // Value of Allowable Gate Power Dissipation in watt
+Es=10; // Trigger Source Voltage in V
+slope=3*10^3; // Slope of Gate-Cathode Characteristic line
+
+// Calculations
+Ig=sqrt(P/slope);
+Vg=slope*Ig;
+Rs=(Es-Vg)/Ig;
+
+printf("(a)The value of Gate Resistance for the Circuit is %0.0f ohm \n",Rs);
+printf("(b)The value of the Gate Voltage is %0.2e V \n",Vg);
+printf("(c)The value of the Gate Current is %0.2e A \n",Ig);
+
+
+// Results
+// (a) The value of Gate Resistance for the Circuit is 2 K-ohm
+// (b) The value of the Gate Voltage is 6 V
+// (c) The value of the Gate Current is 2 mA
\ No newline at end of file |