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authorpriyanka2015-06-24 15:03:17 +0530
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+// Calculate complex voltage gain,Input admittance
+// Basic Electronics
+// By Debashis De
+// First Edition, 2010
+// Dorling Kindersley Pvt. Ltd. India
+// Example 7-52 in page 355
+
+clear; clc; close;
+
+// Given data
+mu=100; // Amplification factor
+rd=40*10^3; // Dynamic resistance in K-ohms
+gm=2.5*10^-3; // Transconductance in mA/V
+Cgs=4*10^-12; // Gate-source capacitance in pF
+Cds=0.6*10^-12; // Drain-source capacitance in pF
+Cgd=2.4*10^-12; // Gate-drain capacitance in pF
+
+// Calculation
+Ygs=%i*2*%pi*10^2*4*10^-12;
+Yds=%i*2*%pi*10^2*0.6*10^-12;
+Ygd=%i*2*%pi*10^2*2.4*10^-12;
+gd=2.5*10^-5;
+Yd=10^-5;
+Av=(-2.5/3.5)*10^2;
+Ci=Cgs+(1-Av)*Cgd;
+printf("Av = %0.2f\nCi = %0.3e F\n",Av,Ci);
+printf("For f=10^6 Hz,\n");
+Ygs1=%i*2.51*10^-6;
+Yds1=%i*0.377*10^-6;
+Ygd=%i*1.51*10^-6;
+Av=((-2.5*3.5*10^2)/12.30)+%i*((2.5*0.188*10^2)/12.30);
+C1=Cgs+(72*Cgd);
+G1=2*%pi*2.4*10^-12*3.82;
+R1=1/G1;
+printf("Av =");
+disp(Av);
+printf("C1 = %0.3e F\nR1 = %0.3e ohms",C1,R1);
+
+// Result
+// Av = -71.4
+// Ci = 177.8 pF
+// At f=10^6 Hz,
+// Av = -71.2+j3.82
+// C1 = 177 pF
+// R1 = 173.5 K-ohms \ No newline at end of file
diff --git a/181/CH7/EX7.52/example7_52.txt b/181/CH7/EX7.52/example7_52.txt
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+Av = -71.43
+Ci = 1.778e-010 F
+For f=10^6 Hz,
+Av =
+ - 71.138211 + 3.8211382i
+C1 = 1.768e-010 F
+R1 = 1.736e+010 ohms \ No newline at end of file