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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /181/CH7/EX7.3 | |
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initial commit / add all books
Diffstat (limited to '181/CH7/EX7.3')
-rwxr-xr-x | 181/CH7/EX7.3/example7_3.sce | 20 | ||||
-rwxr-xr-x | 181/CH7/EX7.3/example7_3.txt | 1 |
2 files changed, 21 insertions, 0 deletions
diff --git a/181/CH7/EX7.3/example7_3.sce b/181/CH7/EX7.3/example7_3.sce new file mode 100755 index 000000000..020697bb3 --- /dev/null +++ b/181/CH7/EX7.3/example7_3.sce @@ -0,0 +1,20 @@ +// Find amplification with 40k resistor instead
+// Basic Electronics
+// By Debashis De
+// First Edition, 2010
+// Dorling Kindersley Pvt. Ltd. India
+// Example 7-3 in page 313
+
+clear; clc; close;
+
+// Given data
+Av=-18.7; // Amplification from prev problem
+R1=2.54; // Resistance value in ohms
+R=40; // Load resistor in K-ohms
+
+// Calculation
+Avs=(Av)*(R1/(R1+R));
+printf("Amplification Avs = %0.2f",Avs);
+
+// Result
+// Avs = -1.11
\ No newline at end of file diff --git a/181/CH7/EX7.3/example7_3.txt b/181/CH7/EX7.3/example7_3.txt new file mode 100755 index 000000000..d6d86cc9d --- /dev/null +++ b/181/CH7/EX7.3/example7_3.txt @@ -0,0 +1 @@ +Amplification Avs = -1.12
\ No newline at end of file |