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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Exa 6.9
+clc;
+clear;
+close;
+//given data
+K=0.0278;// in W/mK
+rho=1.092;// in kg/m^3
+miu=19.57*10^-6;// in kg/ms
+Cp=1007;// in kg/kg degree C
+epsilon=0.9;
+sigma=5.67*10^-8;
+d=75+2*25;// in mm
+d=d*10^-3;// in meter
+T_s=80;// in degree C
+T_infinite=20;// in degree C
+T_f=(T_s+T_infinite)/2;// in degree C
+T_f=T_f+273;// in K
+Bita=1/T_f;
+g=9.81;
+del_T=T_s-T_infinite;
+Pr=miu*Cp/K;
+Gr=(rho^2*g*Bita*del_T*d^3)/miu^2;
+
+// Formula Nu= h*d/K = 0.53*(Gr*Pr)^(1/4);
+h= 0.53*(Gr*Pr)^(1/4)*K/d;
+
+//(a) Heat loss from 6 m length of pipe
+A=%pi*d*6;
+Q_conv=h*A*del_T;
+Q_rad=epsilon*sigma*A*((T_s+273)^4-(T_infinite+273)^4);
+//total heat transfer rate
+Q=Q_conv+Q_rad;
+disp("Total heat transfer rate is : "+string(Q)+" W");
+
+// (b) Overall heat transfer coefficient
+// Formula Q=U*A*del_T
+U=Q/(A*del_T);
+disp("Overall heat transfer coefficient is : "+string(U)+" W/m^2 degree C");