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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Example 6.1
+clc
+ibq=(20-0.7)/1.5
+format(6)
+disp(ibq,"(i) I_BQ(in mA) = V_CC-V_BE / R_B =")
+icq=50*12.87
+format(7)
+disp(icq,"I_CQ(in mA) = beta * I_BQ =")
+disp("(ii) V_CC = I_CQ*R_L + V_CEQ")
+vceq=20-(643.5*16*10^-3)
+format(5)
+disp(vceq,"Therefore, V_CEQ(in V) = V_CC - I_CQ*R_L =")
+format(6)
+pdc=20*643.5*10^-3
+disp(pdc,"(iii) P_DC(in W) = V_CC * I_CQ =")
+disp("(iv) P_ac Peak current i_b = 9 mA")
+ic=50*9
+format(4)
+disp(ic,"i_c(in mA) = beta * i_b =")
+icm=450/sqrt(2)
+format(8)
+disp(icm,"Therefore, i_c(rms) = I_rms(in mA) = i_c(peak) / sqrt(2) =")
+pac=318.19^2*16*10^-6
+format(7)
+disp(pac,"Therefore, P_ac(in W) = (I_rms)^2 * R_L =")
+n=(1.619*100)/12.87
+disp(n,"(v) Efficiency eta(in percentage) = P_ac/P_DC * 100 =")